LeetCode 662 Maximum Width of Binary Tree

题目描述

Given a binary tree, write a function to get the maximum width of the given tree. The width of a tree is the maximum width among all levels. The binary tree has the same structure as a full binary tree, but some nodes are null.

The width of one level is defined as the length between the end-nodes (the leftmost and right most non-null nodes in the level, where the null nodes between the end-nodes are also counted into the length calculation.

Example 1:

Input: 

           1
         /   \
        3     2
       / \     \  
      5   3     9 

Output: 4
Explanation: The maximum width existing in the third level with the length 4 (5,3,null,9).

Example 2:

Input: 

          1
         /  
        3    
       / \       
      5   3     

Output: 2
Explanation: The maximum width existing in the third level with the length 2 (5,3).

Example 3:

Input: 

          1
         / \
        3   2 
       /        
      5      

Output: 2
Explanation: The maximum width existing in the second level with the length 2 (3,2).

Example 4:

Input: 

          1
         / \
        3   2
       /     \  
      5       9 
     /         \
    6           7
Output: 8
Explanation:The maximum width existing in the fourth level with the length 8 (6,null,null,null,null,null,null,7).


Note: Answer will in the range of 32-bit signed integer.

一句话题意

给定二叉树,求二叉树的最大宽度。二叉树某层的宽度是指其最左非空节点与最右非空节点之间的跨度。

解题思路

直接DFS或者BFS遍历二叉树,转为数组储存方式,根节点下标为1,其他叶子节点所处下标为i,则左子树下标为 2 * i , 右子树下标为 2 * i + 1
第i层(i>1)的宽度为最右、最左节点标号之差+1,即数组中下标从(i-1)^2到i^2-1之间,最后一个节点值下标跟第一个节点值下标之差+1。
分类: LeetCode算法设计

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