LeetCode 662 Maximum Width of Binary Tree
题目描述
Given a binary tree, write a function to get the maximum width of the given tree. The width of a tree is the maximum width among all levels. The binary tree has the same structure as a full binary tree, but some nodes are null.
The width of one level is defined as the length between the end-nodes (the leftmost and right most non-null nodes in the level, where the null
nodes between the end-nodes are also counted into the length calculation.
Example 1:
Input: 1 / \ 3 2 / \ \ 5 3 9 Output: 4 Explanation: The maximum width existing in the third level with the length 4 (5,3,null,9).
Example 2:
Input: 1 / 3 / \ 5 3 Output: 2 Explanation: The maximum width existing in the third level with the length 2 (5,3).
Example 3:
Input: 1 / \ 3 2 / 5 Output: 2 Explanation: The maximum width existing in the second level with the length 2 (3,2).
Example 4:
Input: 1 / \ 3 2 / \ 5 9 / \ 6 7 Output: 8 Explanation:The maximum width existing in the fourth level with the length 8 (6,null,null,null,null,null,null,7).
Note: Answer will in the range of 32-bit signed integer.
一句话题意
给定二叉树,求二叉树的最大宽度。二叉树某层的宽度是指其最左非空节点与最右非空节点之间的跨度。
解题思路
直接DFS或者BFS遍历二叉树,转为数组储存方式,根节点下标为1,其他叶子节点所处下标为
第i层(i>1)的宽度为最右、最左节点标号之差+1,即数组中下标从(i-1)^2到i^2-1之间,最后一个节点值下标跟第一个节点值下标之差+1。
i
,则左子树下标为 2 * i
, 右子树下标为 2 * i + 1
。第i层(i>1)的宽度为最右、最左节点标号之差+1,即数组中下标从(i-1)^2到i^2-1之间,最后一个节点值下标跟第一个节点值下标之差+1。
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